(PHP 3 >= 3.0.16, PHP 4, PHP 5)

imagecreatefromjpeg -- Create a new image from file or URL


resource imagecreatefromjpeg ( string filename )

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

imagecreatefromjpeg() returns an empty string on failure. It also outputs an error message, which unfortunately displays as a broken link in a browser. To ease debugging the following example will produce an error JPEG:

Example 1. Example to handle an error during creation (courtesy vic at zymsys dot com )

function LoadJpeg($imgname)
$im = @imagecreatefromjpeg($imgname); /* Attempt to open */
if (!$im) { /* See if it failed */
$im  = imagecreate(150, 30); /* Create a blank image */
$bgc = imagecolorallocate($im, 255, 255, 255);
$tc  = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
/* Output an errmsg */
imagestring($im, 1, 5, 5, "Error loading $imgname", $tc);

Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.

Tip: You can use a URL as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and Appendix L for a list of supported URL protocols.


Windows versions of PHP prior to PHP 4.3.0 do not support accessing remote files via this function, even if allow_url_fopen is enabled.